(x^3+3x2+3x+1)/(x+1)

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Solution for (x^3+3x2+3x+1)/(x+1) equation: 


D( x )

x+1 = 0

x+1 = 0

x+1 = 0

x+1 = 0 // - 1

x = -1

x in (-oo:-1) U (-1:+oo)

(x^3+3*x^2+3*x+1)/(x+1) = 0

x^3+3*x^2+3*x+1 = 0

x^3+3*x^2+3*x+1 = 0

{ 1, -1 }

1

x = 1

x^3+3*x^2+3*x+1 = 8

1

-1

x = -1

x^3+3*x^2+3*x+1 = 0

-1

x+1

x^2+2*x+1

x^3+3*x^2+3*x+1

x+1

-x^3-x^2

2*x^2+3*x+1

-2*x^2-2*x

x+1

-x-1

0

x^2+2*x+1 = 0

DELTA = 2^2-(1*1*4)

DELTA = 0

x = -2/(1*2)

x = -1 or x = -1

x in { -1, -1, -1} 

(x+1)^3 = 0

(x+1)^2 = 0

x+1 = 0 // - 1

x = -1

x in { -1} 

x belongs to the empty set

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